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Write the equation in standard form for the ellipse with center at the origin, vertex (9,0)(-9,0), and co-vertex (0,3)(0,3).

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Q. Write the equation in standard form for the ellipse with center at the origin, vertex (9,0)(-9,0), and co-vertex (0,3)(0,3).
  1. Identify Vertex Value: Identify the value of aa using the vertex.\newlineVertex: (9,0)(-9, 0)\newlinea=a = distance from center to vertex\newlinea=((90)2+(00)2)a = \sqrt{((-9 - 0)^2 + (0 - 0)^2)}\newlinea=81a = \sqrt{81}\newlinea=9a = 9
  2. Identify Co-vertex Value: Identify the value of bb using the co-vertex.\newlineCo-vertex: (0,3)(0, 3)\newlineb=b = distance from center to co-vertex\newlineb=(00)2+(30)2b = \sqrt{(0 - 0)^2 + (3 - 0)^2}\newlineb=9b = \sqrt{9}\newlineb=3b = 3
  3. Write Standard Form Equation: Write the standard form equation of the ellipse.\newlineCenter: (0,0)(0, 0)\newlinea=9a = 9, b=3b = 3\newlineStandard form: (xh)2a2+(yk)2b2=1\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1\newlinePlug in h=0h = 0, k=0k = 0, a=9a = 9, and b=3b = 3:\newline(x0)292+(y0)232=1\frac{(x - 0)^2}{9^2} + \frac{(y - 0)^2}{3^2} = 1\newlinex2/81+y2/9=1x^2/81 + y^2/9 = 1

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