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What is the center of the ellipse ((x−5)29)+((y−2)254)=1\left(\frac{(x - 5)^2}{9}\right) + \left(\frac{(y - 2)^2}{54}\right) = 1?\newlineWrite your answer in simplified, rationalized form.\newline(________ , _______)

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Q. What is the center of the ellipse ((x−5)29)+((y−2)254)=1\left(\frac{(x - 5)^2}{9}\right) + \left(\frac{(y - 2)^2}{54}\right) = 1?\newlineWrite your answer in simplified, rationalized form.\newline(________ , _______)
  1. Identify Standard Form: Identify the standard form of the ellipse equation.\newlineThe standard form of an ellipse equation is (x−h)2/a2+(y−k)2/b2=1(x - h)^2/a^2 + (y - k)^2/b^2 = 1, where (h,k)(h, k) is the center of the ellipse.
  2. Compare with Standard Form: Compare the given equation with the standard form.\newlineThe given equation is (x−5)29+(y−2)254=1\frac{(x - 5)^2}{9} + \frac{(y - 2)^2}{54} = 1. By comparing this with the standard form, we can see that h=5h = 5 and k=2k = 2.
  3. Write Center: Write down the center of the ellipse.\newlineThe center of the ellipse is (h,k)(h, k), which is (5,2)(5, 2) in this case.

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