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Write the equation in standard form for the ellipse with vertices (9,0)(-9,0) and (9,0)(9,0), and co-vertices (0,5)(0,5) and (0,5)(0,-5).

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Q. Write the equation in standard form for the ellipse with vertices (9,0)(-9,0) and (9,0)(9,0), and co-vertices (0,5)(0,5) and (0,5)(0,-5).
  1. Calculate semi-major axis: Vertices are (9,0)(-9,0) and (9,0)(9,0), so the major axis is horizontal and the length of the major axis is 2a2a, where aa is the semi-major axis.\newlineCalculate aa: a=distance from center to vertex=90=9a = \text{distance from center to vertex} = 9 - 0 = 9.
  2. Calculate semi-minor axis: Co-vertices are (0,5)(0,5) and (0,5)(0,-5), so the minor axis is vertical and the length of the minor axis is 2b2b, where bb is the semi-minor axis.\newlineCalculate bb: b=distance from center to co-vertex=50=5b = \text{distance from center to co-vertex} = 5 - 0 = 5.
  3. Find center coordinates: The center (h,k)(h,k) is at the midpoint of the vertices, which is (0,0)(0,0) since the vertices are equidistant from the origin.
  4. Standard form of ellipse equation: The standard form of the equation of an ellipse with a horizontal major axis is (xh)2/a2+(yk)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. Plug in h=0h=0, k=0k=0, a=9a=9, and b=5b=5 into the equation.
  5. Simplify the equation: The equation becomes (x0)2/92+(y0)2/52=1(x-0)^2/9^2 + (y-0)^2/5^2 = 1.\newlineSimplify the equation: x2/81+y2/25=1x^2/81 + y^2/25 = 1.

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