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Write an equation for an ellipse centered at the origin, which has foci at 
(0,+-15) and vertices at 
(0,+-25).

Write an equation for an ellipse centered at the origin, which has foci at (0,±15) (0, \pm 15) and vertices at (0,±25) (0, \pm 25) .

Full solution

Q. Write an equation for an ellipse centered at the origin, which has foci at (0,±15) (0, \pm 15) and vertices at (0,±25) (0, \pm 25) .
  1. Identify coordinates of foci and vertices: Identify the coordinates of the foci and vertices.\newlineFoci: (0,±15)(0, \pm 15)\newlineVertices: (0,±25)(0, \pm 25)\newlineSince both foci and vertices lie on the y-axis, the ellipse is vertical.
  2. Determine values of aa and cc: Determine the values of aa and cc. The distance from the center to a vertex is 'aa', and the distance from the center to a focus is 'cc'. a=25a = 25 (since the vertices are at (0,±25)(0, \pm 25)) c=15c = 15 (since the foci are at (0,±15)(0, \pm 15))
  3. Calculate value of b: Calculate the value of b using the relationship c2=a2b2 c^2 = a^2 - b^2 .\newlinec2=a2b2 c^2 = a^2 - b^2 \newline152=252b2 15^2 = 25^2 - b^2 \newline225=625b2 225 = 625 - b^2 \newlineb2=625225 b^2 = 625 - 225 \newlineb2=400 b^2 = 400 \newlineb=400 b = \sqrt{400} \newlineb=20 b = 20
  4. Write equation in standard form: Write the equation of the ellipse in standard form.\newlineSince the ellipse is vertical, the standard form of the equation is x2b2+y2a2=1 \frac{x^2}{b^2} + \frac{y^2}{a^2} = 1 .\newlineSubstitute the values of a and b:\newlinex2202+y2252=1 \frac{x^2}{20^2} + \frac{y^2}{25^2} = 1 \newlinex2400+y2625=1 \frac{x^2}{400} + \frac{y^2}{625} = 1
  5. Simplify equation if necessary: Simplify the equation if necessary.\newlineThe equation is already in its simplest form, so no further simplification is needed.\newlineFinal equation: x2400+y2625=1 \frac{x^2}{400} + \frac{y^2}{625} = 1

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