Which of the following is an equation of the line in the xy-plane that passes through the point (1,1) and is parallel to the line with equation y=−3x−1 ?Choose 1 answer:(A) y=31x+4B) y=31x+1(c) y=−3x+4(D) y=−3x+1
Q. Which of the following is an equation of the line in the xy-plane that passes through the point (1,1) and is parallel to the line with equation y=−3x−1 ?Choose 1 answer:(A) y=31x+4B) y=31x+1(c) y=−3x+4(D) y=−3x+1
Identify Parallel Lines: Parallel lines have the same slope. The slope of the given line y=−3x−1 is −3.
Point-Slope Form Equation: Use the point-slope form to write the equation of the line that passes through (1,1) with a slope of −3: y−y1=m(x−x1), where m is the slope and (x1,y1) is the point.
Substitute Slope and Point: Plug in the slope −3 and the point (1,1): y−1=−3(x−1).
Simplify Equation: Simplify the equation: y−1=−3x+3.
Isolate y: Add 1 to both sides to get y by itself: y=−3x+3+1.
Combine Like Terms: Combine like terms: y=−3x+4.
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