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What is the length of the major axis of the ellipse x29+y22=1\frac{x^2}{9} + \frac{y^2}{2} = 1?\newlineWrite your answer in simplified, rationalized form.\newline__\_\_

Full solution

Q. What is the length of the major axis of the ellipse x29+y22=1\frac{x^2}{9} + \frac{y^2}{2} = 1?\newlineWrite your answer in simplified, rationalized form.\newline__\_\_
  1. Identify Values: First, let's identify the values of a2a^2 and b2b^2 from the equation of the ellipse. The equation is in the form (x2)/a2+(y2)/b2=1(x^2)/a^2 + (y^2)/b^2 = 1, where a2a^2 is the larger denominator.
  2. Find aa and bb: In our equation, x29+y22=1\frac{x^2}{9} + \frac{y^2}{2} = 1, we see that a2=9a^2 = 9 and b2=2b^2 = 2. Since 9>29 > 2, a2a^2 corresponds to the major axis.
  3. Calculate aa: Now, we find the value of aa by taking the square root of a2a^2. So, a=9=3a = \sqrt{9} = 3.
  4. Major Axis Length: The length of the major axis is 22 times the value of aa, which means it's 2×3=62 \times 3 = 6.

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