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What is the focus of the parabola y=−9x2y = -9x^2?\newlineSimplify any fractions.\newline(______,______)

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Q. What is the focus of the parabola y=−9x2y = -9x^2?\newlineSimplify any fractions.\newline(______,______)
  1. Identify vertex form: Identify the vertex form of the parabola. \newliney=−9x2y = -9x^2 can be written as y=−9(x−0)2+0y = -9(x - 0)^2 + 0, where a=−9a = -9, h=0h = 0, and k=0k = 0.
  2. Calculate value of p: Calculate the value of p using the formula p=14ap = \frac{1}{4a}.p=14∗(−9)p = \frac{1}{4*(-9)}p=−136p = -\frac{1}{36}
  3. Determine focus: Determine the focus of the parabola using the vertex (h,k)(h, k) and the value of pp.\newlineFocus = (h,k+p)(h, k + p)\newlineFocus = (0,0−136)(0, 0 - \frac{1}{36})\newlineFocus = (0,−136)(0, -\frac{1}{36})

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