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What is the focus of the parabola y=9x2+1y = 9x^2 + 1?\newlineSimplify any fractions.\newline(______,______)

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Q. What is the focus of the parabola y=9x2+1y = 9x^2 + 1?\newlineSimplify any fractions.\newline(______,______)
  1. Identify vertex form: Identify the vertex form of the parabola. \newliney=9x2+1y = 9x^2 + 1 is in the form y=a(xh)2+ky = a(x - h)^2 + k, where a=9a = 9, h=0h = 0, and k=1k = 1.
  2. Calculate value of p: Calculate the value of p using the formula p=14ap = \frac{1}{4a}.p=14×9p = \frac{1}{4\times 9}p=136p = \frac{1}{36}
  3. Determine focus: Determine the focus of the parabola using the vertex (h,k)(h, k) and the value of pp. Since the parabola is vertical, the focus is (h,k+p)(h, k + p). Focus = (0,1+136)(0, 1 + \frac{1}{36}) Focus = (0,3736)(0, \frac{37}{36})

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