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What is the focus of the parabola y=7x2y = 7x^2?\newlineSimplify any fractions.\newline(______,______)

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Q. What is the focus of the parabola y=7x2y = 7x^2?\newlineSimplify any fractions.\newline(______,______)
  1. Identify values: Identify the values of aa, hh, and kk using the standard form y=ax2+bx+cy = ax^2 + bx + c, where the vertex form is y=a(x−h)2+ky = a(x - h)^2 + k. For y=7x2y = 7x^2, a=7a = 7, h=0h = 0, and k=0k = 0.
  2. Calculate pp: Calculate the value of pp using the formula p=14ap = \frac{1}{4a}.p=14×7p = \frac{1}{4\times7}p=128p = \frac{1}{28}
  3. Find focus: Find the focus of the parabola using the vertex (h,k)(h, k) and the value of pp.\newlineSince the parabola is vertical, the focus is (h,k+p)(h, k + p).\newlineFocus = (0,0+128)(0, 0 + \frac{1}{28})\newlineFocus = (0,128)(0, \frac{1}{28})

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