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What is the focus of the parabola y=5x2+6y = 5x^2 + 6?\newlineSimplify any fractions.\newline(______,______)

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Q. What is the focus of the parabola y=5x2+6y = 5x^2 + 6?\newlineSimplify any fractions.\newline(______,______)
  1. Identify vertex form: Identify the vertex form of the parabola. \newliney=5x2+6y = 5x^2 + 6 can be written as y=5(x−0)2+6y = 5(x - 0)^2 + 6, where a=5a = 5, h=0h = 0, and k=6k = 6.
  2. Calculate p value: Calculate the value of p using the formula p=14ap = \frac{1}{4a}. p=14×5p = \frac{1}{4\times5} p=120p = \frac{1}{20}
  3. Determine focus: Determine the focus of the parabola using the vertex (h,k)(h, k) and the value of pp.\newlineSince the parabola opens upwards, the focus is at (h,k+p)(h, k + p).\newlineFocus = (0,6+120)(0, 6 + \frac{1}{20})\newlineFocus = (0,6.05)(0, 6.05)

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