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What is the center of the ellipse x2+9y2−18=0x^2 + 9y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse x2+9y2−18=0x^2 + 9y^2 - 18 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Isolate terms with x and y: Now, we need to get the equation in standard form for an ellipse.\newlineDivide both sides by 1818 to isolate the terms with xx and yy.\newlinex218+9y218=1818\frac{x^2}{18} + \frac{9y^2}{18} = \frac{18}{18}
  2. Simplify the equation: Simplify the equation further. x218+y22=1\frac{x^2}{18} + \frac{y^2}{2} = 1
  3. Identify the center: Identify the center of the ellipse.\newlineThe standard form of an ellipse is (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h,k)(h, k) is the center.\newlineHere, we have (x−0)2/18+(y−0)2/2=1(x-0)^2/18 + (y-0)^2/2 = 1, so the center is (0,0)(0, 0).

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