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What is the center of the ellipse x2+3y2−9=0x^2 + 3y^2 - 9 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse x2+3y2−9=0x^2 + 3y^2 - 9 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Isolate variables: Now, we need to get the equation in standard form for an ellipse.\newlineDivide both sides by 99 to isolate the variables.\newlinex29+3y29=99\frac{x^2}{9} + \frac{3y^2}{9} = \frac{9}{9}
  2. Simplify the equation: Simplify the equation. x29+y23=1\frac{x^2}{9} + \frac{y^2}{3} = 1
  3. Identify center: Identify the center of the ellipse.\newlineThe standard form of an ellipse is (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h,k)(h, k) is the center.\newlineHere, the equation is already in standard form with h=0h = 0 and k=0k = 0.\newlineSo, the center is (0,0)(0, 0).

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