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What is the center of the ellipse 8x2+y2−56=08x^2 + y^2 - 56 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 8x2+y2−56=08x^2 + y^2 - 56 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 5656: Divide the entire equation by 5656 to get the standard form of the ellipse equation.\newline(8x256)+(y256)=5656(\frac{8x^2}{56}) + (\frac{y^2}{56}) = \frac{56}{56}
  2. Simplify equation: Simplify the equation by reducing fractions. x27+y256=1\frac{x^2}{7} + \frac{y^2}{56} = 1
  3. Identify center: Identify the center of the ellipse by comparing to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. The center (h,k)(h,k) is at (0,0)(0,0) since there are no terms to shift the ellipse left/right or up/down.

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