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What is the center of the ellipse 5x2+4y2−80=05x^2 + 4y^2 - 80 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Find properties of ellipses from equations in general formright chevron icon

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Q. What is the center of the ellipse 5x2+4y2−80=05x^2 + 4y^2 - 80 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 8080: Now, divide the entire equation by 8080 to get the standard form of the ellipse equation.\newline(5x280)+(4y280)=8080(\frac{5x^2}{80}) + (\frac{4y^2}{80}) = \frac{80}{80}
  2. Simplify fractions: Simplify the fractions to get the standard form. x216+y220=1\frac{x^2}{16} + \frac{y^2}{20} = 1

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