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What is the center of the ellipse 4x2+y2−76=04x^2 + y^2 - 76 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 4x2+y2−76=04x^2 + y^2 - 76 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 7676: Divide the entire equation by 7676 to get the standard form of the ellipse equation.\newline(4x2)/76+(y2)/76=76/76(4x^2)/76 + (y^2)/76 = 76/76\newlineSimplify the fractions.\newlinex2/19+y2/76=1x^2/19 + y^2/76 = 1
  2. Identify center: Identify the center of the ellipse by comparing the equation to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. The center (h,k)(h, k) is at (0,0)(0, 0) since there are no terms to shift the ellipse left/right or up/down.

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