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What is the center of the ellipse 2x2+47y2−94=02x^2 + 47y^2 - 94 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 2x2+47y2−94=02x^2 + 47y^2 - 94 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide and Simplify: Now, divide the entire equation by 9494 to get the standard form of the ellipse equation.\newline2x294+47y294=9494 \frac{2x^2}{94} + \frac{47y^2}{94} = \frac{94}{94} \newlinex2/47+y2/2=1 x^2/47 + y^2/2 = 1
  2. Standard Form of Ellipse Equation: The standard form of an ellipse is (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1, where (h,k)(h, k) is the center.\newlineHere, we have x2/47+y2/2=1x^2/47 + y^2/2 = 1, which can be written as (x−0)2/47+(y−0)2/2=1(x-0)^2/47 + (y-0)^2/2 = 1.\newlineSo, the center of the ellipse is (0,0)(0, 0).

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