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What is the center of the ellipse 2x2+39y2−78=02x^2 + 39y^2 - 78 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 2x2+39y2−78=02x^2 + 39y^2 - 78 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide by 7878: Now, divide the entire equation by 7878 to get the standard form of the ellipse equation.\newlinex278/2+y278/39=1\frac{x^2}{78/2} + \frac{y^2}{78/39} = 1
  2. Simplify denominators: Simplify the denominators. x239+y22=1\frac{x^2}{39} + \frac{y^2}{2} = 1
  3. Identify center: Identify the center of the ellipse by looking at the standard form equation.\newlineThe center is at (h,k)(h, k) where hh and kk are the values that xx and yy are subtracted by in the equation, but since there are no such values, h=0h=0 and k=0k=0.\newlineCenter of the ellipse: (0,0)(0, 0)

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