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What is the center of the ellipse 2x2+21y2−42=02x^2 + 21y^2 - 42 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Q. What is the center of the ellipse 2x2+21y2−42=02x^2 + 21y^2 - 42 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Divide and Simplify: Now, divide the entire equation by 4242 to get the standard form of the ellipse equation.\newline2x242+21y242=4242 \frac{2x^2}{42} + \frac{21y^2}{42} = \frac{42}{42} \newlineSimplify the fractions.\newlinex2/21+y2/2=1 x^2/21 + y^2/2 = 1
  2. Identify Center: Identify the center of the ellipse by comparing the equation to the standard form (x−h)2/a2+(y−k)2/b2=1(x-h)^2/a^2 + (y-k)^2/b^2 = 1. Here, hh and kk are both 00, so the center is at (0,0)(0, 0).

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