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What is the center of the ellipse 13x2+6y2−78=013x^2 + 6y^2 - 78 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)

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Find properties of ellipses from equations in general formright chevron icon

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Q. What is the center of the ellipse 13x2+6y2−78=013x^2 + 6y^2 - 78 = 0?\newlineWrite your answer in simplified, rationalized form.\newline(______,______)
  1. Move constant term: Move the constant term to the right side to isolate the x2x^2 and y2y^2 terms.\newline13x2+6y2=7813x^2 + 6y^2 = 78
  2. Divide by 7878: Divide the entire equation by 7878 to get the standard form of the ellipse equation.\newlinex278/13+y278/6=1\frac{x^2}{78/13} + \frac{y^2}{78/6} = 1
  3. Simplify denominators: Simplify the denominators. x26+y213=1\frac{x^2}{6} + \frac{y^2}{13} = 1

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