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Three points on the graph of the function f(x)f(x) are (0,1)(0,1) (1,2)(1,2) and (2,4)(2,4) which represents f(x)f(x)

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Q. Three points on the graph of the function f(x)f(x) are (0,1)(0,1) (1,2)(1,2) and (2,4)(2,4) which represents f(x)f(x)
  1. Assume Linear Function: We will assume that the function f(x)f(x) is linear since we have only 33 points and a linear function is determined by 22 points. We will use the two-point formula to find the equation of the line.
  2. Calculate Slope: The two-point formula for a line is given by (yy1)=m(xx1)(y - y_1) = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  3. Write Equation of Line: First, we calculate the slope mm using the points (0,1)(0,1) and (1,2)(1,2). The slope mm is given by the change in yy divided by the change in xx, so m=(21)/(10)=1/1=1m = (2 - 1) / (1 - 0) = 1/1 = 1.
  4. Verify Third Point: Now we use the slope m=1m = 1 and one of the points, say (0,1)(0,1), to write the equation of the line. Substituting into the two-point formula, we get (y1)=1(x0)(y - 1) = 1(x - 0), which simplifies to y=x+1y = x + 1.
  5. Identify Math Error: We need to verify that the third point (2,4)(2,4) satisfies the equation y=x+1y = x + 1. Substituting x=2x = 2 into the equation, we get y=2+1=3y = 2 + 1 = 3. However, the yy-coordinate of the third point is 44, not 33. This means there is a math error in our assumption that the function is linear.

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