Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The second derivative of a function 
f is given by

f^('')(x)=sin(x^(2))+cos(2x)-(1)/(2)". "
How many points of inflection does the graph of 
f have on the interval 
1 < x < 4 ?
Use a graphing calculator.
Choose 1 answer:
(A) Two
(B) Three
(C) Four
(D) Five

The second derivative of a function f f is given by\newlinef(x)=sin(x2)+cos(2x)12 f^{\prime \prime}(x)=\sin \left(x^{2}\right)+\cos (2 x)-\frac{1}{2} \text {. } \newlineHow many points of inflection does the graph of f f have on the interval 1<x<4 1<x<4 ?\newlineUse a graphing calculator.\newlineChoose 11 answer:\newline(A) Two\newline(B) Three\newline(C) Four\newline(D) Five

Full solution

Q. The second derivative of a function f f is given by\newlinef(x)=sin(x2)+cos(2x)12 f^{\prime \prime}(x)=\sin \left(x^{2}\right)+\cos (2 x)-\frac{1}{2} \text {. } \newlineHow many points of inflection does the graph of f f have on the interval 1<x<4 1<x<4 ?\newlineUse a graphing calculator.\newlineChoose 11 answer:\newline(A) Two\newline(B) Three\newline(C) Four\newline(D) Five
  1. Find Points of Inflection: To find points of inflection, we need to look at where the second derivative changes sign.
  2. Plot Second Derivative: Use a graphing calculator to plot f(x)=sin(x2)+cos(2x)12f''(x) = \sin(x^2) + \cos(2x) - \frac{1}{2} on the interval 1<x<41 < x < 4.
  3. Identify Potential Points: Identify the xx-values where f(x)f''(x) crosses the xx-axis; these are potential points of inflection.
  4. Count Sign Changes: Count the number of times f(x)f''(x) changes sign around these xx-values.
  5. Determine Points of Inflection: If f(x)f''(x) changes sign from positive to negative or negative to positive, then that xx-value is a point of inflection.
  6. Analyze Sign Changes: After using the graphing calculator, it looks like f(x)f''(x) changes sign three times within the interval.

More problems from Find higher derivatives of rational and radical functions