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The quiz scores for the students in two math dasses are recorded. The line plats below show the 9 scores for each dass.
Complete the fallowing.
(a) The mean for Class A is 13 points, and the mean for Class B is 5 points. Find the distance between the means of Class A and Class B.
Distance between the means: 
◻ point(s)
(b) Find the mean absolute deviation (MAD) for each class.
MAD for Class A: 
◻ point(s)
MAD for Class B: 
◻ point(s)
(c) Fill in the blank below to express the distance between the means as a multiple of the MAD of either data set.
Distance between the means 
=prod times the MAD
(d) Look at the degree of averlap between the data sets.
Also look at your answer from part (c).
Then select the best chaice belaw.
There is a complete overlap and the distance between the means is 0 .
There is a complete overlap and the distance between the means is greater than 5 times the MAD.
There is some averlap and the distance between the means is between 1 times the MAD and 5 times the MAD.
There is some overlap and the distance between the means is between 0 and 1 times the MAD.
There is no owerlap and the distance between the means is greater than 5 times the MAD.
There is no overlap and the distance between the means is between 1 times the MAD and 5 times the MAD.

The quiz scores for the students in two math dasses are recorded. The line plats below show the 99 scores for each dass.\newlineComplete the fallowing.\newline(a) The mean for Class A is 1313 points, and the mean for Class B is 55 points. Find the distance between the means of Class A and Class B.\newlineDistance between the means: \square point(s)\newline(b) Find the mean absolute deviation (MAD) for each class.\newlineMAD for Class A: \square point(s)\newlineMAD for Class B: \square point(s)\newline(c) Fill in the blank below to express the distance between the means as a multiple of the MAD of either data set.\newlineDistance between the means = =\prod times the MAD\newline(d) Look at the degree of averlap between the data sets.\newlineAlso look at your answer from part (c).\newlineThen select the best chaice belaw.\newlineThere is a complete overlap and the distance between the means is 00 .\newlineThere is a complete overlap and the distance between the means is greater than 55 times the MAD.\newlineThere is some averlap and the distance between the means is between 11 times the MAD and 55 times the MAD.\newlineThere is some overlap and the distance between the means is between 00 and 11 times the MAD.\newlineThere is no owerlap and the distance between the means is greater than 55 times the MAD.\newlineThere is no overlap and the distance between the means is between 11 times the MAD and 55 times the MAD.

Full solution

Q. The quiz scores for the students in two math dasses are recorded. The line plats below show the 99 scores for each dass.\newlineComplete the fallowing.\newline(a) The mean for Class A is 1313 points, and the mean for Class B is 55 points. Find the distance between the means of Class A and Class B.\newlineDistance between the means: \square point(s)\newline(b) Find the mean absolute deviation (MAD) for each class.\newlineMAD for Class A: \square point(s)\newlineMAD for Class B: \square point(s)\newline(c) Fill in the blank below to express the distance between the means as a multiple of the MAD of either data set.\newlineDistance between the means = =\prod times the MAD\newline(d) Look at the degree of averlap between the data sets.\newlineAlso look at your answer from part (c).\newlineThen select the best chaice belaw.\newlineThere is a complete overlap and the distance between the means is 00 .\newlineThere is a complete overlap and the distance between the means is greater than 55 times the MAD.\newlineThere is some averlap and the distance between the means is between 11 times the MAD and 55 times the MAD.\newlineThere is some overlap and the distance between the means is between 00 and 11 times the MAD.\newlineThere is no owerlap and the distance between the means is greater than 55 times the MAD.\newlineThere is no overlap and the distance between the means is between 11 times the MAD and 55 times the MAD.
  1. Question Prompt: Question prompt: Find the distance between the means of ClassAClass A and ClassBClass B, the mean absolute deviation (MADMAD) for each class, express the distance between the means as a multiple of the MADMAD, and determine the degree of overlap between the data sets.
  2. Calculate Distance: Calculate the distance between the means of Class A and Class B.\newlineDistance = Mean of Class A - Mean of Class B\newlineDistance = 13513 - 5\newlineDistance = 88 points
  3. Calculate MAD for Class A: To find the MAD for Class A, we need the absolute deviations from the mean for each score, sum them up, and then divide by the number of scores.\newlineAssuming the scores for Class A are given, calculate the absolute deviations, sum them, and divide by the number of scores (99).\newlineMAD for Class A = (Sum of absolute deviations) / 99

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