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Select the outlier in the data set.\newline74,84,86,87,89,91,92,98,12674,84,86,87,89,91,92,98,126

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Q. Select the outlier in the data set.\newline74,84,86,87,89,91,92,98,12674,84,86,87,89,91,92,98,126
  1. Arrange Data Set: Arrange the data set in ascending order if it is not already.\newlineThe data set is already in ascending order: 74,84,86,87,89,91,92,98,12674, 84, 86, 87, 89, 91, 92, 98, 126.
  2. Calculate IQR: Calculate the interquartile range (IQR) of the data set.\newlineFirst, find the first quartile (Q1Q_1) and the third quartile (Q3Q_3).\newlineQ1Q_1 is the median of the first half of the data set: (74,84,86,87)(74, 84, 86, 87), which is (84+86)/2=85(84 + 86) / 2 = 85.\newlineQ3Q_3 is the median of the second half of the data set: (91,92,98,126)(91, 92, 98, 126), which is (92+98)/2=95(92 + 98) / 2 = 95.\newlineIQR=Q3Q1=9585=10IQR = Q_3 - Q_1 = 95 - 85 = 10.
  3. Determine Outlier Boundaries: Determine the outlier boundaries.\newlineLower boundary = Q11.5×IQR=851.5×10=8515=70Q1 - 1.5 \times IQR = 85 - 1.5 \times 10 = 85 - 15 = 70.\newlineUpper boundary = Q3+1.5×IQR=95+1.5×10=95+15=110Q3 + 1.5 \times IQR = 95 + 1.5 \times 10 = 95 + 15 = 110.
  4. Identify Outliers: Identify any values outside the outlier boundaries. The value 126126 is above the upper boundary of 110110, so it is an outlier.

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