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The function 
f is given in three equivalent forms.
Which form most quickly reveals the vertex?
Choose 1 answer:
(A) 
f(x)=-3(x-2)^(2)+27
(B) 
f(x)=-3(x+1)(x-5)
(c) 
f(x)=-3x^(2)+12 x+15
What is the vertex?
Vertex 
=(◻,◻)

The function \newlinef f is given in three equivalent forms.\newlineWhich form most quickly reveals the vertex?\newlineChoose 11 answer:\newline(A) f(x)=3(x2)2+27 f(x)=-3(x-2)^{2}+27 \newline(B) f(x)=3(x+1)(x5) f(x)=-3(x+1)(x-5) \newline(C) f(x)=3x2+12x+15 f(x)=-3x^{2}+12x+15 \newlineWhat is the vertex?\newlineVertex=(,) =(\square,\square)

Full solution

Q. The function \newlinef f is given in three equivalent forms.\newlineWhich form most quickly reveals the vertex?\newlineChoose 11 answer:\newline(A) f(x)=3(x2)2+27 f(x)=-3(x-2)^{2}+27 \newline(B) f(x)=3(x+1)(x5) f(x)=-3(x+1)(x-5) \newline(C) f(x)=3x2+12x+15 f(x)=-3x^{2}+12x+15 \newlineWhat is the vertex?\newlineVertex=(,) =(\square,\square)
  1. Identify Vertex Form: Identify the form that reveals the vertex.\newlineThe vertex form of a parabola is y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Compare Given Forms: Compare the given forms of the function ff.
    (A) f(x)=3(x2)2+27f(x)=-3(x-2)^{2}+27 is already in vertex form.
    (B) f(x)=3(x+1)(x5)f(x)=-3(x+1)(x-5) is in factored form, which does not directly reveal the vertex.
    (C) f(x)=3x2+12x+15f(x)=-3x^{2}+12x+15 is in standard form, which also does not directly reveal the vertex.
  3. Determine Quickest Form: Determine which form most quickly reveals the vertex.\newlineForm (A) is already in vertex form, so it most quickly reveals the vertex of the parabola.
  4. Identify Vertex: Identify the vertex from form (A).\newlineIn form (A), f(x)=3(x2)2+27f(x)=-3(x-2)^{2}+27, we can see that h=2h = 2 and k=27k = 27.\newlineTherefore, the vertex is (2,27)(2, 27).

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