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The equation of an ellipse is given below.

(x^(2))/(67)+(y^(2))/(57)=1
What are the foci of this ellipse?
Choose 1 answer:
(A) 
(10,0) and 
(-10,0)
(B) 
(0,10) and 
(0,-10)
(C) 
(sqrt10,0) and 
(-sqrt10,0)
(D) 
(0,sqrt10) and 
(0,-sqrt10)

The equation of an ellipse is given below.\newlinex267+y257=1 \frac{x^{2}}{67}+\frac{y^{2}}{57}=1 \newlineWhat are the foci of this ellipse?\newlineChoose 11 answer:\newline(A) (10,0) (10,0) and (10,0) (-10,0) \newline(B) (0,10) (0,10) and (0,10) (0,-10) \newline(C) (10,0) (\sqrt{10}, 0) and (10,0) (-\sqrt{10}, 0) \newline(D) (0,10) (0, \sqrt{10}) and (0,10) (0,-\sqrt{10})

Full solution

Q. The equation of an ellipse is given below.\newlinex267+y257=1 \frac{x^{2}}{67}+\frac{y^{2}}{57}=1 \newlineWhat are the foci of this ellipse?\newlineChoose 11 answer:\newline(A) (10,0) (10,0) and (10,0) (-10,0) \newline(B) (0,10) (0,10) and (0,10) (0,-10) \newline(C) (10,0) (\sqrt{10}, 0) and (10,0) (-\sqrt{10}, 0) \newline(D) (0,10) (0, \sqrt{10}) and (0,10) (0,-\sqrt{10})
  1. Identify Ellipse Equation: The given equation of the ellipse is (x267+y257=1)(\frac{x^2}{67} + \frac{y^2}{57} = 1). To find the foci, we need to determine the values of aa and bb, where aa is the semi-major axis and bb is the semi-minor axis. The larger denominator corresponds to the square of the semi-major axis, a2a^2, and the smaller denominator corresponds to the square of the semi-minor axis, b2b^2.
  2. Determine Semi-Major and Semi-Minor Axes: In the given equation, a2=67a^2 = 67 and b2=57b^2 = 57. Therefore, a=67a = \sqrt{67} and b=57b = \sqrt{57}. Since a2>b2a^2 > b^2, the ellipse is horizontal, and the foci will be located along the xx-axis.
  3. Calculate Distance to Foci: To find the foci, we use the formula c2=a2b2c^2 = a^2 - b^2, where cc is the distance from the center to each focus. Let's calculate cc. \newlinec2=6757c^2 = 67 - 57\newlinec2=10c^2 = 10\newlinec=10c = \sqrt{10}
  4. Locate Foci on x-Axis: Since the ellipse is centered at the origin and is horizontal, the foci will be at (±c,0)(\pm c, 0). Therefore, the foci are at (±10,0)(\pm\sqrt{10}, 0).
  5. Final Answer Comparison: The correct answer is (C) (10,0)(\sqrt{10}, 0) and (10,0)(-\sqrt{10}, 0), which matches one of the given choices.

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