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The equation of a parabola is y=x28x+18y = x^2 - 8x + 18. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x28x+18y = x^2 - 8x + 18. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola.\newlineThe vertex form of a parabola is given by y=a(xh)2+ky = a(x - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Consider given equation: Consider the given equation y=x28x+18y = x^2 - 8x + 18.\newlineWe need to complete the square to rewrite this equation in vertex form.
  3. Find square of half: Find the square of half the coefficient of xx. Half the coefficient of xx is 8/2-8/2, which is 4-4. Squaring this gives us (4)2=16(-4)^2 = 16.
  4. Add and subtract square: Add and subtract the square of half the coefficient of xx inside the equation.\newliney=x28x+1616+18y = x^2 - 8x + 16 - 16 + 18\newlineWe add and subtract 1616 to complete the square while keeping the equation balanced.
  5. Rewrite equation by grouping: Rewrite the equation by grouping the perfect square trinomial and combining the constants.\newliney=(x28x+16)16+18y = (x^2 - 8x + 16) - 16 + 18\newliney=(x4)2+2y = (x - 4)^2 + 2\newlineNow the equation is in vertex form, where (h,k)=(4,2)(h, k) = (4, 2).

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