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The equation of a parabola is y=x2−6x+17y = x^2 - 6x + 17. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______

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Q. The equation of a parabola is y=x2−6x+17y = x^2 - 6x + 17. Write the equation in vertex form.\newlineWrite any numbers as integers or simplified proper or improper fractions.\newline______
  1. Identify vertex form: Identify the vertex form of a parabola, which is y=a(x−h)2+ky = a(x - h)^2 + k.
  2. Start with given equation: Start with the given equation y=x2−6x+17y = x^2 - 6x + 17.
  3. Find square of half: Find the square of half the linear coefficient, which is (−62)2=9(-\frac{6}{2})^2 = 9.
  4. Rewrite equation: Rewrite the equation as y=(x2−6x+9)+17−9y = (x^2 - 6x + 9) + 17 - 9 to complete the square.
  5. Simplify equation: Simplify the equation to y=(x−3)2+8y = (x - 3)^2 + 8.

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