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that I am asking is how to view these structure

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Find the axis of symmetry of a parabolaright chevron icon

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Q. that I am asking is how to view these structure
  1. Identify Form and Orientation: Identify the form of the equation and determine the orientation of the parabola.\newlineThe equation x=12(y+3)2+5x = \frac{1}{2}(y + 3)^2 + 5 is in the form x=a(y−k)2+hx = a(y - k)^2 + h, which indicates a horizontal parabola.
  2. Compare with Standard Form: Compare the given equation with the standard form to find hh and kk.\newlineStandard form: x=a(y−k)2+hx = a(y - k)^2 + h\newlineGiven: x=12(y+3)2+5x = \frac{1}{2}(y + 3)^2 + 5\newlineHere, k=−3k = -3 and h=5h = 5.
  3. Determine Axis of Symmetry: Determine the axis of symmetry using the value of kk. For a horizontal parabola in the form x=a(y−k)2+hx = a(y - k)^2 + h, the axis of symmetry is y=ky = k. Thus, the axis of symmetry is y=−3y = -3.

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