Solve the following equation for $x$ . Express your answer in the simplest form. $\newline$ $-(6 x-2)+4=\frac{3}{2}(-4 x+8)-6$ $\newline$

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Algebra 2

Sum of finite series starts from 1

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Q. Solve the following equation for

x

. Express your answer in the simplest form.

\newline

-(6 x-2)+4=\frac{3}{2}(-4 x+8)-6

\newline

Distribute negative sign: First, let's distribute the negative sign on the left side of the equation. $\newline$ $- (6x - 2) + 4 = -6x + 2 + 4$
Combine like terms: Now, combine like terms on the left side. $-6x + 2 + 4 = -6x + 6$
Distribute $(\frac{3}{2}):</b> On the right side, distribute \$(\frac{3}{2})$ to both terms inside the parenthesis. $\newline$ (\frac{$3$}{$2$})(\(-4x + $8$ ) = $-6$ x + $12$
Subtract and simplify: Subtract $12$ from both sides to get the $x$ terms on one side and the constants on the other. $\newline$ $-6x + 6 - 12 = -6x$
Isolate $x$ : Combine like terms on the left side. $-6x - 6 = -6x$
No solution: Now, we try to isolate $x$ , but we see that the $x$ terms cancel out, leaving us with $-6 = 0$ , which is not true. $\newline$ This means there's no solution to the equation.

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Solve the following equation for x x x. Express your answer in the simplest form.\newline−(6x−2)+4=32(−4x+8)−6 -(6 x-2)+4=\frac{3}{2}(-4 x+8)-6 −(6x−2)+4=23​(−4x+8)−6\newline

Solve the following equation for $x$ . Express your answer in the simplest form. $\newline$ $-(6 x-2)+4=\frac{3}{2}(-4 x+8)-6$ $\newline$