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Solve for $k$ . $\newline$ $-2 = -|k|$ $\newline$ Write your answers as integers or as proper or improper fractions in simplest form. $\newline$ $k =$ _ or $k =$ _

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Solve absolute value equations

Full solution

Q. Solve for

k

.

\newline

-2 = -|k|

\newline

Write your answers as integers or as proper or improper fractions in simplest form.

\newline

k =

_____ or

k =

_____

Understand and Isolate Absolute Value: Understand the equation and isolate the absolute value. $\newline$ We have the equation $–2 = –|k|$ . To isolate the absolute value, we can divide both sides by $-1$ . $\newline$ Doing so, we get $2 = |k|$ .
Solve for $k$ : Solve for $k$ . $\newline$ Since $|k|$ represents the absolute value of $k$ , it means $k$ can be either positive or negative but must have a magnitude of $2$ to satisfy the equation $|k| = 2$ . $\newline$ Therefore, $k$ can be $2$ or $-2$ .

More problems from Solve absolute value equations

Question

3 n^{2}=27

\newline

What are the solutions to the given equation?

\newline

1

\newline

n=\sqrt{3}

\newline

n=3

\newline

n=-\sqrt{3}

n=\sqrt{3}

\newline

n=-3

n=3

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Question

\frac{1}{2} c^{2}+3 c=1

\newline

c=f

c=g

be the solutions to the given equation. If

f>g

, which of the following is the value of

f

\newline

1

\newline

-3+\sqrt{2}

\newline

-3+\sqrt{11}

\newline

3+\sqrt{2}

\newline

3+\sqrt{11}

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\newline

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\newline

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\newline

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\newline

x=

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\newline

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Question

\$200

with which to purchase hats and t-shirts that are to be sold at his class' next fundraiser. Each hat costs the same amount of money, and each t-shirt costs the same amount of money. If Aiden spends all his money entirely on hats, he will get

40

hats. If Aiden purchases only t-shirts, he will get

80

t-shirts. Which of the following best models the relationship between the number of hats,

h

, and the number of t-shirts,

t

, that Aiden could purchase with this money?

\newline

1

\newline

40h+80t=400

\newline

80h+40t=200

\newline

5h+2.5t=200

\newline

2.5h+5t=200

Posted 2 months ago