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Let’s check out your problem:
Find the value of
x
x
x
that solves the equation
ln
(
x
−
1
)
+
ln
5
=
2
\ln (x-1)+\ln 5=2
ln
(
x
−
1
)
+
ln
5
=
2
.
\newline
Answer:
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Home
Math Problems
Algebra 2
Solve linear equations
Full solution
Q.
Find the value of
x
x
x
that solves the equation
ln
(
x
−
1
)
+
ln
5
=
2
\ln (x-1)+\ln 5=2
ln
(
x
−
1
)
+
ln
5
=
2
.
\newline
Answer:
Combine Logarithmic Terms:
Combine the logarithmic terms using the property
ln
(
a
)
+
ln
(
b
)
=
ln
(
a
⋅
b
)
\ln(a) + \ln(b) = \ln(a \cdot b)
ln
(
a
)
+
ln
(
b
)
=
ln
(
a
⋅
b
)
.
ln
(
x
−
1
)
+
ln
(
5
)
=
ln
(
(
x
−
1
)
⋅
5
)
\ln(x - 1) + \ln(5) = \ln((x - 1) \cdot 5)
ln
(
x
−
1
)
+
ln
(
5
)
=
ln
((
x
−
1
)
⋅
5
)
Set Equal to
2
2
2
:
Set the combined logarithmic expression equal to
2
2
2
.
ln
(
5
(
x
−
1
)
)
=
2
\ln(5(x - 1)) = 2
ln
(
5
(
x
−
1
))
=
2
Exponentiate Both Sides:
Exponentiate both sides of the equation to remove the natural logarithm, using the property
e
ln
(
a
)
=
a
e^{\ln(a)} = a
e
l
n
(
a
)
=
a
.
\newline
e
ln
(
5
(
x
−
1
)
)
=
e
2
e^{\ln(5(x - 1))} = e^2
e
l
n
(
5
(
x
−
1
))
=
e
2
Simplify Left Side:
Simplify the left side of the equation, knowing that
e
e
e
and
ln
\ln
ln
are inverse functions.
\newline
5
(
x
−
1
)
=
e
2
5(x - 1) = e^2
5
(
x
−
1
)
=
e
2
Calculate
e
2
e^2
e
2
:
Calculate
e
2
e^2
e
2
to get an approximate value.
e
2
≈
7.389
e^2 \approx 7.389
e
2
≈
7.389
Divide to Isolate:
Divide both sides of the equation by
5
5
5
to isolate
(
x
−
1
)
(x - 1)
(
x
−
1
)
.
\newline
(
x
−
1
)
=
e
2
5
(x - 1) = \frac{e^2}{5}
(
x
−
1
)
=
5
e
2
\newline
(
x
−
1
)
≈
7.389
5
(x - 1) \approx \frac{7.389}{5}
(
x
−
1
)
≈
5
7.389
Calculate Division:
Calculate the division to simplify the right side of the equation.
x
−
1
x - 1
x
−
1
≈
1.478
1.478
1.478
Add
1
1
1
to Solve:
Add
1
1
1
to both sides of the equation to solve for
x
x
x
.
x
≈
1.478
+
1
x \approx 1.478 + 1
x
≈
1.478
+
1
x
≈
2.478
x \approx 2.478
x
≈
2.478
More problems from Solve linear equations
Question
3
n
2
=
27
3 n^{2}=27
3
n
2
=
27
\newline
What are the solutions to the given equation?
\newline
Choose
1
1
1
answer:
\newline
(A)
n
=
3
n=\sqrt{3}
n
=
3
\newline
(B)
n
=
3
n=3
n
=
3
\newline
(C)
n
=
−
3
n=-\sqrt{3}
n
=
−
3
and
n
=
3
n=\sqrt{3}
n
=
3
\newline
(D)
n
=
−
3
n=-3
n
=
−
3
and
n
=
3
n=3
n
=
3
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1
2
c
2
+
3
c
=
1
\frac{1}{2} c^{2}+3 c=1
2
1
c
2
+
3
c
=
1
\newline
Let
c
=
f
c=f
c
=
f
and
c
=
g
c=g
c
=
g
be the solutions to the given equation. If
f
>
g
f>g
f
>
g
, which of the following is the value of
f
f
f
?
\newline
Choose
1
1
1
answer:
\newline
(A)
−
3
+
2
-3+\sqrt{2}
−
3
+
2
\newline
(B)
−
3
+
11
-3+\sqrt{11}
−
3
+
11
\newline
(C)
3
+
2
3+\sqrt{2}
3
+
2
\newline
(D)
3
+
11
3+\sqrt{11}
3
+
11
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Question
Find the value of
x
x
x
that solves the equation
ln
(
x
−
3
)
=
1
+
ln
2
\ln (x-3)=1+\ln 2
ln
(
x
−
3
)
=
1
+
ln
2
.
\newline
Answer:
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Question
Find the value of
x
x
x
that solves the equation
ln
(
x
+
3
)
−
ln
2
=
0
\ln (x+3)-\ln 2=0
ln
(
x
+
3
)
−
ln
2
=
0
.
\newline
Answer:
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Question
Find the value of
x
x
x
that solves the equation
ln
(
x
−
3
)
−
3
ln
4
=
ln
10
\ln (x-3)-3 \ln 4=\ln 10
ln
(
x
−
3
)
−
3
ln
4
=
ln
10
.
\newline
Answer:
x
=
x=
x
=
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Question
Find the value of `x`
\newline
6
x
+
32
=
8
x
−
8
6x+32=8x-8
6
x
+
32
=
8
x
−
8
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Question
Aiden has
$
200
\$200
$200
with which to purchase hats and t-shirts that are to be sold at his class' next fundraiser. Each hat costs the same amount of money, and each t-shirt costs the same amount of money. If Aiden spends all his money entirely on hats, he will get
40
40
40
hats. If Aiden purchases only t-shirts, he will get
80
80
80
t-shirts. Which of the following best models the relationship between the number of hats,
h
h
h
, and the number of t-shirts,
t
t
t
, that Aiden could purchase with this money?
\newline
Choose
1
1
1
answer:
\newline
(A)
40
h
+
80
t
=
400
40h+80t=400
40
h
+
80
t
=
400
\newline
(B)
80
h
+
40
t
=
200
80h+40t=200
80
h
+
40
t
=
200
\newline
(C)
5
h
+
2.5
t
=
200
5h+2.5t=200
5
h
+
2.5
t
=
200
\newline
(D)
2.5
h
+
5
t
=
200
2.5h+5t=200
2.5
h
+
5
t
=
200
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Question
You pick a card at random, put it back, and then pick another card at random.
\newline
4
4
4
\newline
5
5
5
\newline
6
6
6
\newline
7
7
7
\newline
What is the probability of picking a number greater than
5
5
5
and then picking a
4
4
4
?
\newline
Write your answer as a percentage.
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