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Question
Find the slope of the line tangent to the graph of 
f(x)=-3x^(2)-3x+2 at 
x=1.

Question\newlineFind the slope of the line tangent to the graph of f(x)=3x23x+2 f(x)=-3 x^{2}-3 x+2 at x=1 x=1 .

Full solution

Q. Question\newlineFind the slope of the line tangent to the graph of f(x)=3x23x+2 f(x)=-3 x^{2}-3 x+2 at x=1 x=1 .
  1. Find Derivative: First, let's find the derivative of f(x)=3x23x+2f(x) = -3x^2 - 3x + 2.\newlineUsing the power rule, the derivative f(x)f'(x) is:\newlinef(x)=ddx(3x2)+ddx(3x)+ddx(2)f'(x) = \frac{d}{dx}(-3x^2) + \frac{d}{dx}(-3x) + \frac{d}{dx}(2)\newlinef(x)=6x3f'(x) = -6x - 3
  2. Evaluate at x=1x=1: Now, we'll evaluate the derivative at x=1x=1 to find the slope of the tangent line.f(1)=6(1)3f'(1) = -6(1) - 3f(1)=63f'(1) = -6 - 3f(1)=9f'(1) = -9

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