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Q9. The sum of two integers is 116. If one of them is -79 , find the other integers.
Q10. Write five pair of integers 
(m,n) such that 
m÷n=-3. One of such pair is 
(-6,2
Q11. What number should be added to the sum of 345 and 67 to make it equal to the 3-digit number
Q12. Verify the following:

(-22)×[(-4)+(-5)]=[(-22)×(-4)]+[(-22)×(-5)]

Q99. The sum of two integers is 116116. If one of them is 79-79 , find the other integers.\newlineQ1010. Write five pair of integers (m,n) (m, n) such that m÷n=3 m \div n=-3 . One of such pair is (6,2 (-6,2 \newlineQ1111. What number should be added to the sum of 345345 and 6767 to make it equal to the 33-digit number\newlineQ1212. Verify the following:\newline(22)×[(4)+(5)]=[(22)×(4)]+[(22)×(5)] (-22) \times[(-4)+(-5)]=[(-22) \times(-4)]+[(-22) \times(-5)]

Full solution

Q. Q99. The sum of two integers is 116116. If one of them is 79-79 , find the other integers.\newlineQ1010. Write five pair of integers (m,n) (m, n) such that m÷n=3 m \div n=-3 . One of such pair is (6,2 (-6,2 \newlineQ1111. What number should be added to the sum of 345345 and 6767 to make it equal to the 33-digit number\newlineQ1212. Verify the following:\newline(22)×[(4)+(5)]=[(22)×(4)]+[(22)×(5)] (-22) \times[(-4)+(-5)]=[(-22) \times(-4)]+[(-22) \times(-5)]
  1. Find Integer xx: Let's call the other integer xx. We know that 79+x=116-79 + x = 116. To find xx, we add 7979 to both sides of the equation.\newlinex=116+79x = 116 + 79\newlinex=195x = 195
  2. Pairs of Integers: Now let's find five pairs of integers m,nm, n such that m÷n=3m \div n = -3. We already have one pair (6,2) (-6, 2) . Let's find four more. Second pair: (3,1) (3, -1) because 3÷1=33 \div -1 = -3. Third pair: (9,3) (-9, 3) because 9÷3=3 -9 \div 3 = -3. Fourth pair: (6,2) (6, -2) because 6÷2=36 \div -2 = -3. Fifth pair: (12,4) (-12, 4) because m÷n=3m \div n = -300.
  3. Add to Make 33-Digit: To find the number that should be added to the sum of 345345 and 6767 to make it a 33-digit number, we first add 345345 and 6767.345+67=412345 + 67 = 412Since 412412 is already a 33-digit number, we don't need to add anything.
  4. Verify Equation: Let's verify the equation (22)×[(4)+(5)]=[(22)×(4)]+[(22)×(5)](-22)\times[(-4)+(-5)]=[(-22)\times(-4)]+[(-22)\times(-5)].\newlineFirst, calculate the left side:\newline(22)×[(4)+(5)]=(22)×(9)=198(-22)\times[(-4)+(-5)] = (-22)\times(-9) = 198\newlineNow, calculate the right side:\newline[(22)×(4)]+[(22)×(5)]=(88)+(110)=198[(-22)\times(-4)]+[(-22)\times(-5)] = (88) + (110) = 198\newlineSince both sides equal 198198, the equation is verified.

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