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P(x)=2x^(4)-x^(3)+2x^(2)-k
where 
k is an unknown integer.

P(x) divided by 
(x+1) has a remainder of 2 .
What is the value of 
k ?

k=

P(x)=2x4x3+2x2k P(x)=2 x^{4}-x^{3}+2 x^{2}-k \newlinewhere k k is an unknown integer.\newlineP(x) P(x) divided by (x+1) (x+1) has a remainder of 22 .\newlineWhat is the value of k k ?\newlinek= k=

Full solution

Q. P(x)=2x4x3+2x2k P(x)=2 x^{4}-x^{3}+2 x^{2}-k \newlinewhere k k is an unknown integer.\newlineP(x) P(x) divided by (x+1) (x+1) has a remainder of 22 .\newlineWhat is the value of k k ?\newlinek= k=
  1. Apply Remainder Theorem: To find the value of kk, we will use the Remainder Theorem, which states that if a polynomial P(x)P(x) is divided by (xc)(x - c), the remainder is P(c)P(c). Since we are dividing by (x+1)(x + 1), we will find P(1)P(-1).
  2. Substitute x=1x = -1: Substitute x=1x = -1 into the polynomial P(x)=2x4x3+2x2kP(x) = 2x^4 - x^3 + 2x^2 - k.\newlineP(1)=2(1)4(1)3+2(1)2kP(-1) = 2(-1)^4 - (-1)^3 + 2(-1)^2 - k\newlineP(1)=2(1)(1)+2(1)kP(-1) = 2(1) - (-1) + 2(1) - k\newlineP(1)=2+1+2kP(-1) = 2 + 1 + 2 - k\newlineP(1)=5kP(-1) = 5 - k
  3. Set P(1)P(-1) equal to 22: According to the problem, the remainder when P(x)P(x) is divided by (x+1)(x + 1) is 22. Therefore, we set P(1)P(-1) equal to 22.\newline5k=25 - k = 2
  4. Solve for k: Solve for k.\newline5k=25 - k = 2\newlinek=52k = 5 - 2\newlinek=3k = 3

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