Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Algebra 2
Evaluate recursive formulas for sequences
Solve for
b
b
b
.
\newline
b
−
(
−
633
)
=
839
b - (-633) = 839
b
−
(
−
633
)
=
839
\newline
b
=
b =
b
=
Get tutor help
\begin{tabular}{|l|c|}
\newline
\hline b.
m
∠
2
=
m \angle 2=
m
∠2
=
&
107
107
107
\\
\newline
\hline c.
m
∠
3
=
m \angle 3=
m
∠3
=
&
23
23
23
\\
\newline
\hline d.
m
∠
4
=
m \angle 4=
m
∠4
=
&
23
23
23
\\
\newline
\hline e.
m
∠
5
=
m \angle 5=
m
∠5
=
&
157
157
157
\\
\newline
\hline f.
m
∠
6
=
m \angle 6=
m
∠6
=
&
23
23
23
\\
\newline
\hline g.
m
∠
7
=
m \angle 7=
m
∠7
=
& g \\
\newline
\hline
\newline
\end{tabular}
\newline
2
2
2
. If
m
∠
9
=
9
7
∘
m \angle 9=97^{\circ}
m
∠9
=
9
7
∘
and
m
∠
12
=
11
4
∘
m \angle 12=114^{\circ}
m
∠12
=
11
4
∘
, find the measure of each missing angle.
\newline
\begin{tabular}{|l|l|l|}
\newline
\hline a.
m
∠
1
=
m \angle 1=
m
∠1
=
& f.
m
∠
6
=
m \angle 6=
m
∠6
=
& k.
m
∠
3
=
m \angle 3=
m
∠3
=
0
0
0
\\
\newline
\hline b.
m
∠
2
=
m \angle 2=
m
∠2
=
& g.
m
∠
7
=
m \angle 7=
m
∠7
=
&
1
1
1
.
m
∠
3
=
m \angle 3=
m
∠3
=
3
3
3
\\
\newline
\hline C.
m
∠
3
=
m \angle 3=
m
∠3
=
& h.
m
∠
3
=
m \angle 3=
m
∠3
=
5
5
5
& m.
m
∠
3
=
m \angle 3=
m
∠3
=
6
6
6
\\
\newline
\hline d.
m
∠
4
=
m \angle 4=
m
∠4
=
& i.
m
∠
3
=
m \angle 3=
m
∠3
=
8
8
8
& n.
m
∠
3
=
m \angle 3=
m
∠3
=
9
9
9
\\
\newline
\hline e.
m
∠
5
=
m \angle 5=
m
∠5
=
& j.
m
∠
4
=
m \angle 4=
m
∠4
=
1
1
1
& \\
\newline
\hline
\newline
\end{tabular}
\newline
3
3
3
. If
m
∠
4
=
m \angle 4=
m
∠4
=
2
2
2
and
m
∠
4
=
m \angle 4=
m
∠4
=
3
3
3
, find the measure of each missing angle.
\newline
\begin{tabular}{|l|l|l|}
\newline
\hline a.
m
∠
1
=
m \angle 1=
m
∠1
=
& d.
m
∠
6
=
m \angle 6=
m
∠6
=
& g.
m
∠
3
=
m \angle 3=
m
∠3
=
8
8
8
\\
\newline
\hline b.
m
∠
4
=
m \angle 4=
m
∠4
=
& e.
m
∠
7
=
m \angle 7=
m
∠7
=
& \\
\newline
\hline C.
m
∠
5
=
m \angle 5=
m
∠5
=
& f.
m
∠
5
=
m \angle 5=
m
∠5
=
0
0
0
& \\
\newline
\hline
\newline
\end{tabular}
Get tutor help
18
18
18
.T Test
\newline
A
B
C
D
ABCD
A
BC
D
is a parallelogram. Identify
\newline
C
D
CD
C
D
.
\newline
C
D
=
13
CD=13
C
D
=
13
\newline
C
D
=
26
CD=26
C
D
=
26
\newline
C
D
=
52
CD=52
C
D
=
52
\newline
Previous
Get tutor help
21
21
21
.
103
x
+
51
y
=
617
…
103 x+51 y=617 \ldots
103
x
+
51
y
=
617
…
(i),
97
x
+
49
y
=
583
97 x+49 y=583
97
x
+
49
y
=
583
\newline
22
22
22
.
23
x
−
29
y
=
98
,
29
x
−
23
y
=
110
23 x-29 y=98,29 x-23 y=110
23
x
−
29
y
=
98
,
29
x
−
23
y
=
110
.
Get tutor help
Find
a
2
a_2
a
2
and
a
3
a_3
a
3
.
a
1
=
10
a_1=10
a
1
=
10
a
n
=
a
n
−
1
+
3
a_n=a_{n-1}+3
a
n
=
a
n
−
1
+
3
Write your answers as integers or fractions in simplest form.
a
2
=
a_2=
a
2
=
a
3
=
a_3=
a
3
=
Get tutor help
P
(
x
)
=
x
4
−
2
x
3
+
k
x
−
4
P(x)=x^{4}-2 x^{3}+k x-4
P
(
x
)
=
x
4
−
2
x
3
+
k
x
−
4
\newline
where
k
k
k
is an unknown integer.
\newline
P
(
x
)
P(x)
P
(
x
)
divided by
(
x
−
1
)
(x-1)
(
x
−
1
)
has a remainder of
0
0
0
.
\newline
What is the value of
k
k
k
?
\newline
k
=
k=
k
=
Get tutor help
P
(
x
)
=
x
4
−
3
x
2
+
k
x
−
2
P(x)=x^{4}-3 x^{2}+k x-2
P
(
x
)
=
x
4
−
3
x
2
+
k
x
−
2
\newline
where
k
k
k
is an unknown integer.
\newline
P
(
x
)
P(x)
P
(
x
)
divided by
(
x
−
2
)
(x-2)
(
x
−
2
)
has a remainder of
10
10
10
.
\newline
What is the value of
k
k
k
?
\newline
k
=
k=
k
=
Get tutor help
P
(
x
)
=
2
x
4
−
x
3
+
2
x
2
−
k
P(x)=2 x^{4}-x^{3}+2 x^{2}-k
P
(
x
)
=
2
x
4
−
x
3
+
2
x
2
−
k
\newline
where
k
k
k
is an unknown integer.
\newline
P
(
x
)
P(x)
P
(
x
)
divided by
(
x
+
1
)
(x+1)
(
x
+
1
)
has a remainder of
2
2
2
.
\newline
What is the value of
k
k
k
?
\newline
k
=
k=
k
=
Get tutor help
Lea solves the equation below by first squaring both sides of the equation.
\newline
3
+
2
y
=
−
y
3+2 y=\sqrt{-y}
3
+
2
y
=
−
y
\newline
What extraneous solution does Lea obtain?
\newline
y
=
y=
y
=
Get tutor help
Tessa solves the equation below by first squaring both sides of the equation.
\newline
x
2
−
3
x
−
6
=
x
−
1
\sqrt{x^{2}-3 x-6}=x-1
x
2
−
3
x
−
6
=
x
−
1
\newline
What extraneous solution does Tessa obtain?
\newline
x
=
x=
x
=
Get tutor help
Li Juan solves the equation below by first squaring both sides of the equation.
\newline
3
−
2
w
=
w
+
6
\sqrt{3-2 w}=w+6
3
−
2
w
=
w
+
6
\newline
What extraneous solution does
L
i
\mathrm{Li}
Li
Juan obtain?
\newline
w
=
w=
w
=
Get tutor help
Zhang Li solves the equation below by first squaring both sides of the equation.
\newline
−
4
=
5
z
+
7
-4=\sqrt{5 z+7}
−
4
=
5
z
+
7
\newline
What extraneous solution does Zhang Li obtain?
\newline
z
=
z=
z
=
Get tutor help
Avery solves the equation below by first squaring both sides of the equation.
\newline
z
2
+
8
=
1
−
2
z
\sqrt{z^{2}+8}=1-2 z
z
2
+
8
=
1
−
2
z
\newline
What extraneous solution does Avery obtain?
\newline
z
=
z=
z
=
Get tutor help
Addison solves the equation below by first squaring both sides of the equation.
\newline
2
x
−
1
=
8
−
x
2 x-1=\sqrt{8-x}
2
x
−
1
=
8
−
x
\newline
What extraneous solution does Addison obtain?
\newline
x
=
x=
x
=
Get tutor help
Kaylee solves the equation below by first squaring both sides of the equation.
\newline
1
−
y
=
2
y
2
−
7
1-y=\sqrt{2 y^{2}-7}
1
−
y
=
2
y
2
−
7
\newline
What extraneous solution does Kaylee obtain?
\newline
y
=
y=
y
=
Get tutor help
Rania solves the equation below by first squaring both sides of the equation.
\newline
−
5
=
3
x
−
7
-5=\sqrt{3 x-7}
−
5
=
3
x
−
7
\newline
What extraneous solution does Rania obtain?
\newline
x
=
x=
x
=
Get tutor help
Miku solves the equation below by first squaring both sides of the equation.
\newline
z
2
+
2
z
−
3
=
z
−
3
\sqrt{z^{2}+2 z-3}=z-3
z
2
+
2
z
−
3
=
z
−
3
\newline
What extraneous solution does Miku obtain?
\newline
z
=
z=
z
=
Get tutor help
z
=
−
302
+
19.3
i
z=-302+19.3 i
z
=
−
302
+
19.3
i
\newline
What is the real part of
z
z
z
?
\newline
What is the imaginary part of
z
z
z
?
Get tutor help
z
=
−
19
i
+
14
z=-19 i+14
z
=
−
19
i
+
14
\newline
What is the real part of
z
z
z
?
\newline
What is the imaginary part of
z
z
z
?
Get tutor help
z
=
91
−
27
i
z=91-27 i
z
=
91
−
27
i
\newline
What is the real part of
z
z
z
?
\newline
What is the imaginary part of
z
z
z
?
Get tutor help
If
(
x
,
y
)
(x, y)
(
x
,
y
)
is a solution to the system of equations shown, what is the product of the
y
y
y
-coordinates of the solutions?
\newline
x
2
+
4
y
2
=
40
x^{2}+4 y^{2}=40
x
2
+
4
y
2
=
40
\newline
x
+
2
y
=
8
x+2 y=8
x
+
2
y
=
8
Get tutor help
If
(
x
,
y
)
(x, y)
(
x
,
y
)
is a solution to the system of equations shown, what is the product of the
y
y
y
-coordinates of the solutions?
\newline
x
2
+
y
2
=
9
x^{2}+y^{2}=9
x
2
+
y
2
=
9
\newline
x
+
y
=
3
x+y=3
x
+
y
=
3
Get tutor help
8
y
=
4
x
2
−
12
x
+
46
8 y=4 x^{2}-12 x+46
8
y
=
4
x
2
−
12
x
+
46
\newline
y
=
3
2
x
+
5
4
y=\frac{3}{2} x+\frac{5}{4}
y
=
2
3
x
+
4
5
\newline
If
(
a
,
b
)
(a, b)
(
a
,
b
)
is the solution to the system of equations shown, what is the value of
a
a
a
?
Get tutor help
5
y
=
3478
−
3
c
5 y=3478-3 c
5
y
=
3478
−
3
c
\newline
In the given equation,
c
c
c
is a constant. If
y
=
8
y=8
y
=
8
is a solution to the equation, what is the value of
c
c
c
?
Get tutor help
Find
a
2
a_2
a
2
and
a
3
a_3
a
3
.
a
1
=
1
a_1 = 1
a
1
=
1
a
n
=
8
a
n
−
1
a_n = 8a_{n - 1}
a
n
=
8
a
n
−
1
Write your answers as integers or fractions in simplest form.
a
2
=
a_2 =
a
2
=
______
a
3
=
a_3 =
a
3
=
______
Get tutor help
