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Find a2a_2 and a3a_3. a1=1a_1 = 1 an=8an−1a_n = 8a_{n - 1} Write your answers as integers or fractions in simplest form. a2=a_2 = ______ a3=a_3 = ______

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Q. Find a2a_2 and a3a_3. a1=1a_1 = 1 an=8an−1a_n = 8a_{n - 1} Write your answers as integers or fractions in simplest form. a2=a_2 = ______ a3=a_3 = ______
  1. Finding a2a_2: We are given the recursive formula an=8an−1a_n = 8a_{n - 1} and the initial value a1=1a_1 = 1. To find a2a_2, we substitute n=2n = 2 into the formula.\newlinea2=8a2−1=8a1a_2 = 8a_{2 - 1} = 8a_1\newlineSince a1=1a_1 = 1, we have:\newlinea2=8×1=8a_2 = 8 \times 1 = 8
  2. Finding a3a_3: Next, we find a3a_3 by substituting n=3n = 3 into the recursive formula.\newlinea3=8a3−1=8a2a_3 = 8a_{3 - 1} = 8a_2\newlineWe already found that a2=8a_2 = 8, so we can substitute this value in:\newlinea3=8×8=64a_3 = 8 \times 8 = 64

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