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Find a2a_2 and a3a_3. a1=10a_1=10 an=an−1+3a_n=a_{n-1}+3 Write your answers as integers or fractions in simplest form. a2=a_2= a3=a_3=

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Q. Find a2a_2 and a3a_3. a1=10a_1=10 an=an−1+3a_n=a_{n-1}+3 Write your answers as integers or fractions in simplest form. a2=a_2= a3=a_3=
  1. Given Sequence and Formula: We are given the first term of the sequence: a1=10a_1 = 10 We need to find the second term, a2a_2, using the recursive formula: an=an−1+3a_n = a_{n-1} + 3
  2. Find a2a_2: To find a2a_2, we substitute n=2n = 2 into the recursive formula:\newlinea2=a2−1+3a_2 = a_{2-1} + 3\newlinea2=a1+3a_2 = a_1 + 3\newlineNow we substitute the value of a1a_1:\newlinea2=10+3a_2 = 10 + 3\newlinea2=13a_2 = 13
  3. Find a3a_3: Next, we find a3a_3 using the same recursive formula:\newlinea3=a3−1+3a_3 = a_{3-1} + 3\newlinea3=a2+3a_3 = a_2 + 3\newlineWe already found a2a_2 to be 1313, so we substitute that value:\newlinea3=13+3a_3 = 13 + 3\newlinea3=16a_3 = 16

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