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Maddy is carrying a 5liter5\,\text{liter} jug of sports drink that weighs 7.5kg7.5\,\text{kg}. She wants to know how many kilograms a 2liter2\,\text{liter} jug of sports drink would weigh (w)(w). She assumes the relationship between volume and weight is proportional. What is the weight of the 2liter2\,\text{liter} jug?

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Q. Maddy is carrying a 5liter5\,\text{liter} jug of sports drink that weighs 7.5kg7.5\,\text{kg}. She wants to know how many kilograms a 2liter2\,\text{liter} jug of sports drink would weigh (w)(w). She assumes the relationship between volume and weight is proportional. What is the weight of the 2liter2\,\text{liter} jug?
  1. Identify Given Information: Identify the given information and what is being asked.\newlineMaddy has a 55-liter jug of sports drink that weighs 7.57.5 kg. We need to find the weight of a 22-liter jug of sports drink, assuming the relationship between volume and weight is proportional.
  2. Set Up Proportion: Set up the proportion to find the weight of the 22-liter jug.\newlineSince the relationship between volume and weight is proportional, we can set up the following proportion:\newlineWeight of 5-liter jugVolume of 5-liter jug=Weight of 2-liter jugVolume of 2-liter jug\frac{\text{Weight of } 5\text{-liter jug}}{\text{Volume of } 5\text{-liter jug}} = \frac{\text{Weight of } 2\text{-liter jug}}{\text{Volume of } 2\text{-liter jug}}\newline7.5 kg5 liters=w2 liters\frac{7.5 \text{ kg}}{5 \text{ liters}} = \frac{w}{2 \text{ liters}}
  3. Solve for Unknown Weight: Solve for the unknown weight ww of the 22-liter jug.\newlineCross-multiply to solve for ww:\newline7.5kg×2liters=5liters×w7.5 \, \text{kg} \times 2 \, \text{liters} = 5 \, \text{liters} \times w\newline15kg=5liters×w15 \, \text{kg} = 5 \, \text{liters} \times w
  4. Divide to Isolate Weight: Divide both sides of the equation by 5 liters5 \text{ liters} to isolate ww. \newline15 kg5 liters=w\frac{15 \text{ kg}}{5 \text{ liters}} = w\newlinew=3 kgw = 3 \text{ kg}

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