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Recently, frogs have been disappearing from the wild due to a contagious fungus. To monitor the current population in a certain region, Alan collects 2828 frogs, marks them, and releases them. Later, he collects 110110 frogs and finds that 1111 of them are marked. To the nearest whole number, what is the best estimate for the frog population? ____\_\_\_\_

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Q. Recently, frogs have been disappearing from the wild due to a contagious fungus. To monitor the current population in a certain region, Alan collects 2828 frogs, marks them, and releases them. Later, he collects 110110 frogs and finds that 1111 of them are marked. To the nearest whole number, what is the best estimate for the frog population? ____\_\_\_\_
  1. Given Information: We are given the following information:\newline- Alan marks and releases 2828 frogs.\newline- Later, he collects 110110 frogs, out of which 1111 are marked.\newlineWe need to estimate the total frog population in the region based on this data.\newlineWe will use the capture-recapture method, which assumes that the proportion of marked frogs in the second sample represents the same proportion of the total population.
  2. Proportion Setup: Set up a proportion to represent the relationship between the marked and unmarked frogs in the second sample and the total population.\newlineLet p p be the estimated frog population.\newlineThe proportion is as follows:\newlinemarked frogs in second sampletotal frogs in second sample=total marked frogsestimated total population \frac{\text{marked frogs in second sample}}{\text{total frogs in second sample}} = \frac{\text{total marked frogs}}{\text{estimated total population}} \newline11110=28p \frac{11}{110} = \frac{28}{p}
  3. Cross Multiplication: Cross multiply to solve for pp:11×p=28×11011 \times p = 28 \times 110
  4. Solving for p: Now, divide both sides of the equation by 1111 to solve for pp:\newline(11p)/11=(28110)/11(11 \cdot p) / 11 = (28 \cdot 110) / 11\newlinep=(28110)/11p = (28 \cdot 110) / 11
  5. Calculating p: Calculate the value of p:\newlinep = (28×110)/11(28 \times 110) / 11\newlinep = 3080/113080 / 11\newlinep = 280280

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