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In which direction does the parabola y+3x2=1y + 3x^2 = 1 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left

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Q. In which direction does the parabola y+3x2=1y + 3x^2 = 1 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left
  1. Identify Parabola Type: y+3x2=1y + 3x^2 = 1\newlineIdentify if the parabola is vertical or horizontal.\newlineSince the xx term is squared, it's a vertical parabola.
  2. Rearrange Equation: y+3x2=1y + 3x^2 = 1\newlineRearrange the equation to isolate yy.\newlineSubtract 11 from both sides.\newliney+3x2−1=1−1y + 3x^2 - 1 = 1 - 1\newliney=−3x2y = -3x^2
  3. Determine Parabola Direction: y=−3x2y = -3x^2\newlineDetermine the direction the parabola opens.\newlineThe coefficient of x2x^2 is −3-3, so a=−3a = -3.\newlineSince a<0a < 0, the parabola opens downwards.

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