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In which direction does the parabola y−10x2=3y - 10x^2 = 3 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left

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Q. In which direction does the parabola y−10x2=3y - 10x^2 = 3 open?\newlineChoices:\newline(A) up\newline(B) down\newline(C) right\newline(D) left
  1. Identify Parabola Orientation: Identify if the parabola is vertical or horizontal.\newliney−10x2=3y - 10x^2 = 3 has a squared xx term.\newlineIt's a vertical parabola.
  2. Rearrange Equation to Standard Form: Rearrange the equation to standard form by isolating yy. Add 10x210x^2 to both sides. y−10x2+10x2=3+10x2y - 10x^2 + 10x^2 = 3 + 10x^2 y=10x2+3y = 10x^2 + 3
  3. Determine Parabola Opening Direction: Determine the direction the parabola opens. The coefficient of x2x^2 is 1010, so a=10a = 10. a>0a > 0, the parabola opens up.

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