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In which direction does the parabola x−3y2=−4x - 3y^2 = -4 open?\newlineChoices:\newline(A)up\newline(B)down\newline(C)right\newline(D)left

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Q. In which direction does the parabola x−3y2=−4x - 3y^2 = -4 open?\newlineChoices:\newline(A)up\newline(B)down\newline(C)right\newline(D)left
  1. Identify Parabola Orientation: Identify if the parabola is vertical or horizontal. x−3y2=−4x - 3y^2 = -4 has a squared yy term, so it's horizontal.
  2. Rearrange Equation to Standard Form: Rearrange the equation to standard form by isolating xx.x−3y2+3y2=−4+3y2x - 3y^2 + 3y^2 = -4 + 3y^2x=3y2−4x = 3y^2 - 4
  3. Determine Parabola Opening Direction: Determine the direction of the parabola opening. The coefficient of y2y^2 is 33, so a=3a = 3. Since a>0a > 0, the parabola opens to the right.

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