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In the 
xy-plane, the graph of the equation 
y=3(x+6)^(2)+5 has a 
y intercept of 
(0,b). What is the value of 
b ?

In the xy x y -plane, the graph of the equation y=3(x+6)2+5 y=3(x+6)^{2}+5 has a y y intercept of (0,b) (0, b) . What is the value of b b ?

Full solution

Q. In the xy x y -plane, the graph of the equation y=3(x+6)2+5 y=3(x+6)^{2}+5 has a y y intercept of (0,b) (0, b) . What is the value of b b ?
  1. Set xx to 00: To find the y-intercept, we set xx to 00 in the equation y=3(x+6)2+5y=3(x+6)^{2}+5.\newlineCalculation: y=3(0+6)2+5y=3(0+6)^{2}+5
  2. Simplify equation: Simplify the equation by calculating the square of 66.\newlineCalculation: y=3(6)2+5y=3(6)^2+5
  3. Calculate square: Calculate 66 squared which is 3636.\newlineCalculation: y=3(36)+5y=3(36)+5
  4. Multiply by 33: Multiply 33 by 3636 to get 108108.\newlineCalculation: y=108+5y=108+5
  5. Add 55: Add 55 to 108108 to get the final value of yy.\newlineCalculation: y=113y=113

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