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In the figure below, m/_2=45^(@) and m/_XWY=133^(@). Find m/_1. m/_1=◻" 。 "

In the figure below, m∠2=45∘ m \angle 2=45^{\circ} and m∠XWY=133∘ m \angle X W Y=133^{\circ} .\newlineFind m∠1 m \angle 1 .\newlinem∠1=□ 。  m \angle 1=\square \text { 。 }

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Q. In the figure below, m∠2=45∘ m \angle 2=45^{\circ} and m∠XWY=133∘ m \angle X W Y=133^{\circ} .\newlineFind m∠1 m \angle 1 .\newlinem∠1=□ 。  m \angle 1=\square \text { 。 }
  1. Linear Pair Calculation: Angle 22 is given as 4545 degrees, and angle XWY is given as 133133 degrees. Since angles 11 and 22 form a linear pair, their measures add up to 180180 degrees.\newlineCalculation: m/1+m/2=180∘m/_{1} + m/_{2} = 180^{\circ}\newlineSubstitute m/2=45∘m/_{2} = 45^{\circ} into the equation.\newlinem/1+45∘=180∘m/_{1} + 45^{\circ} = 180^{\circ}\newlinem/1=180∘−45∘m/_{1} = 180^{\circ} - 45^{\circ}\newlinem/1=135∘m/_{1} = 135^{\circ}
  2. Angle Sum Calculation: Now, we need to check if angle 11 and angle XWY form a linear pair as well. If they do, then m/_1+m/_XWYm/\_1 + m/\_XWY should equal 180180 degrees.\newlineCalculation: m/_1+m/_XWY=180∘m/\_1 + m/\_XWY = 180^{\circ}\newlineSubstitute m/_XWY=133∘m/\_XWY = 133^{\circ} and m/_1=47∘m/\_1 = 47^{\circ} into the equation.\newline47∘+133∘=180∘47^{\circ} + 133^{\circ} = 180^{\circ}

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