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In the diagram below of circle 
O, chords 
bar(AB) and 
bar(CD) intersect at 
E.
If 
m/_AEC=34 and 
mAC^(⏜)=50, what is 
mDB^(⏜) ?

In the diagram below of circle O O , chords AB \overline{A B} and CD \overline{C D} intersect at E E .\newlineIf mAEC=34 \mathrm{m} \angle A E C=34 and \mathrm{m} \overparen{A C}=50 , what is \mathrm{m} \overparen{D B} ?

Full solution

Q. In the diagram below of circle O O , chords AB \overline{A B} and CD \overline{C D} intersect at E E .\newlineIf mAEC=34 \mathrm{m} \angle A E C=34 and \mathrm{m} \overparen{A C}=50 , what is \mathrm{m} \overparen{D B} ?
  1. Vertical Angles Congruence: Since AEAE and CDCD intersect at EE inside the circle, angles AEC\angle AEC and DEB\angle DEB are vertical angles and therefore congruent.\newlinem/DEB=m/AEC=34m/\angle DEB = m/\angle AEC = 34^\circ.
  2. Sum of Angles in Same Segment: The angles AECAEC and ACBACB are part of the same segment, so their measures add up to mACmAC^{\bigcirc}.ACB=mACAEC=5034=16\angle ACB = mAC^{\bigcirc} - \angle AEC = 50^\circ - 34^\circ = 16^\circ.
  3. Inscribed Angle Property: The angle ACBACB is inscribed in the arc ABCABC, so the measure of arc ABCABC is twice the measure of angle ACBACB. \newlinemAB=2×mACB=2×16=32m_{AB}^{\bigcirc} = 2 \times m_{\angle ACB} = 2 \times 16^\circ = 32^\circ.
  4. Rest of the Circle: The full circle is 360360 degrees, so the measure of arc DBDB is the rest of the circle minus arc ABCABC.\newlinemDB=360m_{DB}^{\bigcirc} = 360 degrees mAB=360- m_{AB}^{\bigcirc} = 360 degrees 32- 32 degrees =328= 328 degrees.

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