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Identify the part of the circle given the equation. 10. (x-10)^(2)+(y-5)^(2)=28 radius : ◻ sqrt() ◻ circumference: ◻ (round to tenths)

Identify the part of the circle given the equation.\newline1010. (x−10)2+(y−5)2=28 (x-10)^{2}+(y-5)^{2}=28 \newlineradius : □ \square \sqrt{ } □ \square \newlinecircumference: □ \square (round to tenths)

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Q. Identify the part of the circle given the equation.\newline1010. (x−10)2+(y−5)2=28 (x-10)^{2}+(y-5)^{2}=28 \newlineradius : □ \square \sqrt{ } □ \square \newlinecircumference: □ \square (round to tenths)
  1. Identify Circle Equation: Identify the equation of the circle and its components.\newlineThe equation given is (x−10)2+(y−5)2=28(x-10)^2 + (y-5)^2 = 28. This represents a circle with center at (1010, 55) and radius squared equals 2828.
  2. Calculate Radius: Calculate the radius of the circle.\newlineTo find the radius, take the square root of 2828:\newlineradius=28=4×7=27≈5.3 \text{radius} = \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7} \approx 5.3
  3. Calculate Circumference: Calculate the circumference of the circle.\newlineUsing the formula for circumference, C=2πrC = 2\pi r:\newlineC=2π×27≈2×3.1416×5.3≈33.3 C = 2\pi \times 2\sqrt{7} \approx 2 \times 3.1416 \times 5.3 \approx 33.3

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