Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Given the likelihood function;


" Lf "=(1)/(sigma^(n)(sqrt2( bar(x)))^(n))exp(-(-1//2sum(Y_(i)-beta_(1)-beta_(2)x_(2i))^(2))/(sigma^(2)))
(a) Derive the log likelihood function as a function of 
beta_(1),beta_(2), and 
sigma^(2).
Scanned with CamScanner
(b) Choose. 
beta_(1),beta_(2), and 
sigma^(2) to maximize the log likefihood function.
(c) Dexive the maximum liketihood enor variance. Is it the same as the ceast equare minimization error variance? If nit, state the condition under which the two error vasiances will be the same.

22. Given the likelihood function;\newline Lf =1σn(2xˉ)nexp(1/2(Yiβ1β2x2i)2σ2) \text { Lf }=\frac{1}{\sigma^{n}(\sqrt{2} \bar{x})^{n}} \exp \left(-\frac{-1 / 2 \sum\left(Y_{i}-\beta_{1}-\beta_{2} x_{2 i}\right)^{2}}{\sigma^{2}}\right) \newline(a) Derive the log likelihood function as a function of β1,β2 \beta_{1}, \beta_{2} , and σ2 \sigma^{2} .\newlineScanned with CamScanner\newline(b) Choose. β1,β2 \beta_{1}, \beta_{2} , and σ2 \sigma^{2} to maximize the log likefihood function.\newline(c) Dexive the maximum liketihood enor variance. Is it the same as the ceast equare minimization error variance? If nit, state the condition under which the two error vasiances will be the same.

Full solution

Q. 22. Given the likelihood function;\newline Lf =1σn(2xˉ)nexp(1/2(Yiβ1β2x2i)2σ2) \text { Lf }=\frac{1}{\sigma^{n}(\sqrt{2} \bar{x})^{n}} \exp \left(-\frac{-1 / 2 \sum\left(Y_{i}-\beta_{1}-\beta_{2} x_{2 i}\right)^{2}}{\sigma^{2}}\right) \newline(a) Derive the log likelihood function as a function of β1,β2 \beta_{1}, \beta_{2} , and σ2 \sigma^{2} .\newlineScanned with CamScanner\newline(b) Choose. β1,β2 \beta_{1}, \beta_{2} , and σ2 \sigma^{2} to maximize the log likefihood function.\newline(c) Dexive the maximum liketihood enor variance. Is it the same as the ceast equare minimization error variance? If nit, state the condition under which the two error vasiances will be the same.
  1. Take Natural Logarithm: To derive the log likelihood function, take the natural logarithm of the likelihood function "Lf". log(Lf)=log(1σn(2π)n)12((Yiβ1β2xi)2σ2)\log(L_f) = \log\left(\frac{1}{\sigma^{n}(\sqrt{2\pi})^n}\right) - \frac{1}{2} \cdot \sum\left(\frac{(Y_i - \beta_1 - \beta_2 \cdot x_i)^2}{\sigma^2}\right)
  2. Simplify Log Likelihood: Simplify the log likelihood function by distributing the logarithm. \newlinelog(Lf)=nlog(σ)nlog(2π)12((Yiβ1β2xi)2)/(σ2)\log(L_f) = -n \cdot \log(\sigma) - n \cdot \log(\sqrt{2\pi}) - \frac{1}{2} \cdot \sum\left((Y_i - \beta_1 - \beta_2 \cdot x_i)^2\right)/(\sigma^2)
  3. Maximize Log Likelihood: To maximize the log likelihood function, take partial derivatives with respect to β1\beta_1, β2\beta_2, and σ2\sigma^2 and set them to zero.\newlinelog(Lf)β1=0\frac{\partial\log(L_f)}{\partial\beta_1} = 0, log(Lf)β2=0\frac{\partial\log(L_f)}{\partial\beta_2} = 0, log(Lf)σ2=0\frac{\partial\log(L_f)}{\partial\sigma^2} = 0
  4. Solve System of Equations: Solve the system of equations from the partial derivatives to find the values of β1\beta_1, β2\beta_2, and σ2\sigma^2 that maximize the log likelihood function.\newlineThis involves solving a system of equations which is not shown here.
  5. Derive Error Variance: Derive the maximum likelihood error variance by finding the second derivative of the log likelihood function with respect to σ2\sigma^2 and evaluating it at the maximum likelihood estimates.\newlineThis step involves calculus which is not shown here.
  6. Compare Variances: Compare the maximum likelihood error variance to the least squares minimization error variance. The comparison involves understanding the relationship between the two variances under certain conditions, which is not shown here.

More problems from Find equations of tangent lines using limits