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Given an equation 6+4x2x2=06 + 4x - 2x^2 = 0. (a) Express 6+4x2x26 + 4x - 2x^2 in the form a(x+b)2a - (x + b)^2

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Q. Given an equation 6+4x2x2=06 + 4x - 2x^2 = 0. (a) Express 6+4x2x26 + 4x - 2x^2 in the form a(x+b)2a - (x + b)^2
  1. Arrange in Descending Order: We need to complete the square to express the given quadratic equation in the form a(x+b)2a - (x + b)^2. The first step is to arrange the equation in descending order of the powers of xx. \newline6+4x2x26 + 4x - 2x^2 rearranged is 2x2+4x+6-2x^2 + 4x + 6.
  2. Factor Out Coefficient: Next, we factor out the coefficient of the x2x^2 term from the x2x^2 and xx terms.\newlineThis gives us 2(x22x)+6-2(x^2 - 2x) + 6.
  3. Find Value of b: Now, we need to find the value of bb in the expression (x+b)2(x + b)^2 that will complete the square. The term bb is half of the coefficient of xx, which is 2-2 in this case.\newlineSo, b=2/2=1b = -2 / 2 = -1.
  4. Add/Subtract b2b^2: We add and subtract b2b^2 inside the parentheses to complete the square. Since b=1b = -1, b2=(1)2=1b^2 = (-1)^2 = 1. We add and subtract 11 inside the parentheses, which gives us 2(x22x+11)+6-2(x^2 - 2x + 1 - 1) + 6.
  5. Write as Perfect Square: Now we can write the expression as a perfect square: 2((x1)21)+6-2((x - 1)^2 - 1) + 6.
  6. Distribute 2-2: Next, we distribute the 2-2 inside the parentheses: 2(x1)2+2+6-2(x - 1)^2 + 2 + 6.
  7. Combine Constant Terms: Finally, we combine the constant terms: 2(x1)2+8-2(x - 1)^2 + 8.

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