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For the function 
f(x)=x^(2)-4, find the slope of the tangent line at 
x=3.
Answer:

For the function f(x)=x24 f(x)=x^{2}-4 , find the slope of the tangent line at x=3 x=3 .\newlineAnswer:

Full solution

Q. For the function f(x)=x24 f(x)=x^{2}-4 , find the slope of the tangent line at x=3 x=3 .\newlineAnswer:
  1. Calculate Derivative of Function: To find the slope of the tangent line at a specific point on a function, we need to calculate the derivative of the function. The derivative of a function at a point gives us the slope of the tangent line at that point.\newlineFor the function f(x)=x24f(x) = x^2 - 4, we will find the derivative f(x)f'(x).\newlinef(x)=ddx(x24)f'(x) = \frac{d}{dx} (x^2 - 4)\newlinef(x)=2xf'(x) = 2x
  2. Find Derivative at Specific Point: Now that we have the derivative, we can find the slope of the tangent line at x=3x = 3 by evaluating the derivative at that point.f(3)=2(3)f'(3) = 2(3)f(3)=6f'(3) = 6
  3. Evaluate Slope at x=3x = 3: We have found the slope of the tangent line at x=3x = 3 to be 66. This is the final step in solving the problem.

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