Q. 2. For the function f(x)=∣3x−9∣, evaluate the left and right limits of f(x) as x approaches 2 .a. limx→2−f(x)b. limx→2+f(x)
Consider Values Less Than 2: To find the left-hand limit as x approaches 2, we need to consider the values of x that are just less than 2. For these values, the expression inside the absolute value, 3x−9, will be negative because 3(2)−9=6−9=−3. Therefore, the absolute value function will negate the inside expression to make it positive.
Write Left-Hand Limit Expression: We can write the expression for the left-hand limit as: limx→2−f(x)=limx→2−∣3x−9∣Since 3x−9 is negative when x is just less than 2, we can remove the absolute value by negating the expression inside:limx→2−f(x)=limx→2−−(3x−9)
Evaluate Left-Hand Limit: Now we can evaluate the limit by substituting x with a value just less than 2:x→2−limf(x)=−(3(2)−9)=−(6−9)=−(−3)=3
Consider Values Greater Than 2: To find the right-hand limit as x approaches 2, we need to consider the values of x that are just greater than 2. For these values, the expression inside the absolute value, 3x−9, will be negative or positive depending on whether x is closer to 2 or further away. However, since we are considering values just greater than 2, the expression 3x−9 will still be negative because 3(2)−9=6−9=−3. Therefore, the absolute value function will negate the inside expression to make it positive.
Write Right-Hand Limit Expression: We can write the expression for the right-hand limit as: limx→2+f(x)=limx→2+∣3x−9∣Since 3x−9 is negative when x is just greater than 2, we can remove the absolute value by negating the expression inside:limx→2+f(x)=limx→2+−(3x−9)
Evaluate Right-Hand Limit: Now we can evaluate the limit by substituting x with a value just greater than 2:x→2+limf(x)=−(3(2)−9)=−(6−9)=−(−3)=3